JEE Mains · Chemistry · STD 12 - 8.2 Carboxylic acids and their derivative
The correct sequential addition of reagents in the preparation of \(3 -\)nitrobenzoic acid from benzene is:
- A \(\mathrm{Br}_{2} / \mathrm{AlBr}_{3}, \mathrm{HNO}_{3} / \mathrm{H}_{2} \mathrm{SO}_{4}, \mathrm{Mg} /\) ether, \(\mathrm{CO}_{2}, \mathrm{H}_{3} \mathrm{O}^{+}\)
- B \(\mathrm{Br}_{2} / \mathrm{AlBr}_{3}, \mathrm{NaCN}, \mathrm{H}_{3} \mathrm{O}^{+}, \mathrm{HNO}_{3} / \mathrm{H}_{2} \mathrm{SO}_{4}\)
- C \(\mathrm{Br}_{2} / \mathrm{AlBr}_{3}, \mathrm{HNO}_{3} / \mathrm{H}_{2} \mathrm{SO}_{4}, \mathrm{NaCN}, \mathrm{H}_{3} \mathrm{O}^{+}\)
- D \(\mathrm{HNO}_{3} / \mathrm{H}_{2} \mathrm{SO}_{4}, \mathrm{Br}_{2} / \mathrm{AlBr}_{3}, \mathrm{Mg} /\) ether, \(\mathrm{CO}_{2}, \mathrm{H}_{3} \mathrm{O}^{+}\)
Answer & Solution
Correct Answer
(D) \(\mathrm{HNO}_{3} / \mathrm{H}_{2} \mathrm{SO}_{4}, \mathrm{Br}_{2} / \mathrm{AlBr}_{3}, \mathrm{Mg} /\) ether, \(\mathrm{CO}_{2}, \mathrm{H}_{3} \mathrm{O}^{+}\)
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