JEE Mains · Chemistry · STD 12 - 8.2 Carboxylic acids and their derivative
The correct sequence of reagents for the preparation of \(Q\) and \(R\) is :

- A \((i)\) \(Cr _2 O _3, 770\,K , 20\,atm\); \((ii)\) \(CrO _2 Cl _2, H _3 O ^{+}\); \((iii)\) \(NaOH\); \((iv)\) \(H _3 O ^{+}\)
- B \((i)\) \(CrO _2 Cl _2, H _3 O ^{+}\); \((ii)\) \(Cr _2 O _3, 770\,K , 20\,atm\); \((iii)\) \(NaOH\); \((iv)\) \(H _3 O ^{+}\)
- C \((i)\) \(KMnO _4, OH ^{-}\); \((ii)\) \(Mo _2 O _3, A\); \((iii)\) \(NaOH\); \((iv)\) \(H _3 O ^{+}\)
- D \((i)\) \(Mo _2 O _3, \Delta\); \((ii)\) \(CrO _2 Cl _2, H _3 O ^{+}\); \((iii)\) \(NaOH\); \((iv)\) \(H _3 O ^{+}\)
Answer & Solution
Correct Answer
(A) \((i)\) \(Cr _2 O _3, 770\,K , 20\,atm\); \((ii)\) \(CrO _2 Cl _2, H _3 O ^{+}\); \((iii)\) \(NaOH\); \((iv)\) \(H _3 O ^{+}\)
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