JEE Mains · Chemistry · STD 11 - 9. Hydricarbon
The correct sequence of correct reagents for the following transformation is
- A \((i)\) \(\mathrm{Fe}, \mathrm{HCl}\,\,(\mathrm{ii}) \mathrm{NaNO}_{2}, \mathrm{HCl}, 0^{\circ} \mathrm{C}\,\,(\mathrm{iii}) \mathrm{H}_{2} \mathrm{O} / \mathrm{H}^{+}\,\,(\mathrm{iv}) \mathrm{Cl}_{2}, \mathrm{FeCl}_{3}\)
- B \((i)\) \(\mathrm{Cl}_{2}, \mathrm{FeCl}_{3}\,\,(\mathrm{ii}) \mathrm{NaNO}_{2}, \mathrm{HCl}, 0^{\circ} \mathrm{C}\,\,(\mathrm{iii}) \mathrm{Fe}, \mathrm{HCl}\,\,(\mathrm{iv}) \mathrm{H}_{2} \mathrm{O} / \mathrm{H}^{+}\)
- C \((i)\) \(\mathrm{Fe}, \mathrm{HCl}\,\,(\mathrm{ii}) \mathrm{Cl}_{2}, \mathrm{HCl}\,\,(\mathrm{iii}) \mathrm{NaNO}_{2}, \mathrm{HCl}, 0^{\circ} \mathrm{C}\,\,(\mathrm{iv}) \mathrm{H}_{2} \mathrm{O} / \mathrm{H}^{+}\)
- D \((i)\) \(\mathrm{Cl}_{2}, \mathrm{FeCl}_{3}\,\,(\mathrm{ii}) \mathrm{Fe}, \mathrm{HCl}\,\,(\mathrm{iii}) \mathrm{NaNO}_{2}, \mathrm{HCl}, 0^{\circ} \mathrm{C}\,\,(\mathrm{iv}) \mathrm{H}_{2} \mathrm{O} / \mathrm{H}^{+}\)
Answer & Solution
Correct Answer
(D) \((i)\) \(\mathrm{Cl}_{2}, \mathrm{FeCl}_{3}\,\,(\mathrm{ii}) \mathrm{Fe}, \mathrm{HCl}\,\,(\mathrm{iii}) \mathrm{NaNO}_{2}, \mathrm{HCl}, 0^{\circ} \mathrm{C}\,\,(\mathrm{iv}) \mathrm{H}_{2} \mathrm{O} / \mathrm{H}^{+}\)
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