JEE Mains · Chemistry · STD 12 -8.1. Aldehydes and ketones
The compound \(A\) in the following reaction is : \(A\xrightarrow[{(ii)\,\,Conc.\,{H_2}S{O_4}/\Delta }]{{{\text{(i)}}\,{\text{C}}{{\text{H}}_3}MgBr/{H_2}O}}\) \(B\xrightarrow[{(ii)\,Zn/{H_2}O}]{{(i)\,{O_3}}}C + D\) \(D\xrightarrow[\Delta ]{{Ba\left( {OH} \right)}}\begin{array}{*{20}{c}} {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_3}} \\ {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|} \\ {{H_3}C - C} \end{array}\)\(\begin{array}{*{20}{c}} {\,\,\,\,\,\,\,O} \\ {\,\,\,\,\,||} \\ { = CH - C - C{H_3}} \end{array}\)
- B \(\begin{array}{*{20}{c}} {O\,\,\,\,\,\,\,} \\ {||\,\,\,\,\,\,\,\,} \\ {{C_6}{H_5} - C - C{H_2}C{H_3}} \end{array}\)
- C \(\begin{array}{*{20}{c}} {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O\,} \\ {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,||} \\ {{C_6}{H_5} - C{H_2} - C - C{H_3}} \end{array}\)
- D \(\begin{array}{*{20}{c}} {\,\,\,\,\,O\,} \\ {\,\,||} \\ {{C_6}{H_5} - C - C{H_3}} \end{array}\)
Answer & Solution
Correct Answer
(C) \(\begin{array}{*{20}{c}} {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O\,} \\ {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,||} \\ {{C_6}{H_5} - C{H_2} - C - C{H_3}} \end{array}\)
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