JEE Mains · Chemistry · STD 12 - 8.2 Carboxylic acids and their derivative
Reaction of an inorganic sulphite \(X\) with dilute \(H _{2} SO _{4}\) generates compound \(Y\). Reaction of \(Y\) with \(NaOH\) gives \(X\). Further, the reaction of \(X\) with \(Y\) and water affords compound \(Z\). \(Y\) and \(Z ,\) respectively, are:
- A \(S\) and \(Na _{2} SO _{3}\)
- B \(SO _{2}\) and \(NaHSO _{3}\)
- C \(SO _{3}\) and \(NaHSO _{3}\)
- D \(SO _{2}\) and \(Na _{2} SO _{3}\)
Answer & Solution
Correct Answer
(B) \(SO _{2}\) and \(NaHSO _{3}\)
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