JEE Mains · Chemistry · STD 12 - 6. Haloalkanes and Haloarenes
For the following reactions \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{Br}+\mathrm{Z}^{-}\)\(\xrightarrow[{{\text{Sublimation}}}]{{{k_s}}} \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{Z}+\mathrm{Br}^{-}\) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{Br}+\mathrm{Z}^{-}\)\(\xrightarrow[{{\text{elimination}}}]{{{k_e}}}\mathrm{CH}_{3} \mathrm{CH}= \mathrm{CH}_{2} +\mathrm{HZ}+\mathrm{Br}^{-}\) where \(\mathrm{Z}^{-}=\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{O}^{-}(\mathrm{A})\) or \(\begin{array}{*{20}{c}}
{\,C{H_3}} \\
{|\,\,\,\,\,} \\
{C{H_3} - C - {O^ - }(B)} \\
{|\,\,\,\,} \\
{\,\,C{H_3}}
\end{array}\) \(\mathrm{k}_{\mathrm{s}}\) and \(\mathrm{k}_{\mathrm{e}},\) are \(,\) respectively, the rate constants for the substitution and elimination, and \(\mu=\frac{\mathrm{k}_{\mathrm{s}}}{\mathrm{k}_{\mathrm{e}}},\) the correct options is
- A \(\mu_{\mathrm{B}}>\mu_{\mathrm{A}}\) and \(\mathrm{k}_{\mathrm{e}}(\mathrm{B})>\mathrm{k}_{\mathrm{e}}(\mathrm{A})\)
- B \(\mu_{\mathrm{B}}>\mu_{\mathrm{A}}\) and \(\mathrm{k}_{\mathrm{e}}(\mathrm{A})>\mathrm{k}_{\mathrm{e}}(\mathrm{B})\)
- C \(\mu_{\mathrm{A}}>\mu_{\mathrm{B}}\) and \(\mathrm{k}_{\mathrm{e}}(\mathrm{B})>\mathrm{k}_{\mathrm{e}}(\mathrm{A})\)
- D \(\mu_{\mathrm{A}}>\mu_{\mathrm{B}}\) and \(\mathrm{k}_{e}(\mathrm{A})>\mathrm{k}_{\mathrm{e}}(\mathrm{B})\)
Answer & Solution
Correct Answer
(C) \(\mu_{\mathrm{A}}>\mu_{\mathrm{B}}\) and \(\mathrm{k}_{\mathrm{e}}(\mathrm{B})>\mathrm{k}_{\mathrm{e}}(\mathrm{A})\)
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