JEE Mains · Chemistry · STD 12 - 9. Amines
For reaction
The correct order of set of reagents for the above conversion is _______.
- A \(\mathrm{Br}_2 \mid \mathrm{FeBr}_3, \mathrm{H}_2 \mathrm{O}(\Delta), \mathrm{NaOH}\)
- B \(\mathrm{H}_2 \mathrm{SO}_4, \mathrm{Ac}_2 \mathrm{O}, \mathrm{Br}_2, \mathrm{H}_2 \mathrm{O}(\Delta), \mathrm{NaOH}\)
- C \(\mathrm{Ac}_2 \mathrm{O}, \mathrm{Br}_2, \mathrm{H}_2 \mathrm{O}(\Delta), \mathrm{NaOH}\)
- D \(\mathrm{Ac}_2 \mathrm{O}, \mathrm{H}_2 \mathrm{SO}_4, \mathrm{Br}_2, \mathrm{NaOH}\)
Answer & Solution
Correct Answer
(B) \(\mathrm{H}_2 \mathrm{SO}_4, \mathrm{Ac}_2 \mathrm{O}, \mathrm{Br}_2, \mathrm{H}_2 \mathrm{O}(\Delta), \mathrm{NaOH}\)
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