JEE Mains · Chemistry · STD 11 - 9. Hydricarbon
\(\mathrm{CH}_3-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{Br}+\mathrm{NaOH} \xrightarrow{\mathrm{C}_2 \mathrm{H}_5 \mathrm{OH}}\) Product '\(A\)' 
Consider the above reactions, identify product B and product C.
- A \(B=C=2\)-Propanol
- B \(B=2\)-Propanol \(C=1\)-Propanol
- C \(B=1\)-Propanol \(C=2\)-Propanol
- D \(B=C=1\)-Propanol
Answer & Solution
Correct Answer
(B) \(B=2\)-Propanol \(C=1\)-Propanol
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