JEE Mains · Chemistry · STD 12 - p -Block elements - ll
An inorganic Compound \('\mathrm{X}^{\prime}\) on treatment with concentrated \(\mathrm{H}_{2} \mathrm{SO}_{4}\) produces brown fumes and gives dark brown ring with \(\mathrm{FeSO}_{4}\) in presence of concentrated \(\mathrm{H}_{2} \mathrm{SO}_{4} .\) Also Compound \('\mathrm{X}'\) gives precipitate \('Y',\) when its solution in dilute \(\mathrm{HCI}\) is treated with \(\mathrm{H}_{2} \mathrm{~S}\) gas. The precipitate \('Y'\) on treatment with concentrated \(\mathrm{HNO}_{3}\) followed by excess of \(\mathrm{NH}_{4} \mathrm{OH}\) further gives deep blue coloured solution, Compound \('X'\) is :
- A \(\mathrm{Cu}\left(\mathrm{NO}_{3}\right)_{2}\)
- B \(\mathrm{Pb}\left(\mathrm{NO}_{3}\right)_{2}\)
- C \(\mathrm{Pb}\left(\mathrm{NO}_{2}\right)_{2}\)
- D \(\mathrm{Co}\left(\mathrm{NO}_{3}\right)_{2}\)
Answer & Solution
Correct Answer
(A) \(\mathrm{Cu}\left(\mathrm{NO}_{3}\right)_{2}\)
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