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JEE Mains · Chemistry · STD 12 - 8.2 Carboxylic acids and their derivative
A solution of m-chloroaniline, \(m-\)chlorophenol and \(\mathrm{m}\) -chlorobenzoic acid in ethyl acetate was extracted initially with a saturated solution of \(\mathrm{NaHCO}_{3}\) to give fraction \(\mathrm{A}\). The left over organic phase was extracted with dilute \(NaOH\) solution to give fraction \(\mathrm{B}\). The final organic layer was labelled as fraction \(\mathrm{C}\). Fractions \(\mathrm{A},\mathrm{B}\) and \(\mathrm{C},\) contain respectively
- A \(\mathrm{m}\) -chlorobenzoic acid, \(\mathrm{m}\) -chloroaniline and \(\mathrm{m}\)-chlorophenol
- B \(\mathrm{m}\) -chloroaniline, \(\mathrm{m}\) -chlorobenzoic acid and \(\mathrm{m}\) -chlorophenol
- C \(\mathrm{m}\) -chlorobenzoic acid, \(\mathrm{m}\) -chlorophenol and \(\mathrm{m}\) -chloroaniline
- D \(\mathrm{m}\) -chlorophenol, \(\mathrm{m}\) -chlorobenzoic acid and \(\mathrm{m}\) -chloroaniline
Answer & Solution
Correct Answer
(C) \(\mathrm{m}\) -chlorobenzoic acid, \(\mathrm{m}\) -chlorophenol and \(\mathrm{m}\) -chloroaniline
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