JEE Mains · Chemistry · STD 12 - 9. Amines
A reaction of \(0.1\) mole of Benzylamine with bromomethane gave \(23\, g\) of Benzyl trimethyl ammonium bromide. The number of moles of bromomethane consumed in this reaction are \(n \times 10^{-1},\) when \(n =\ldots...\) (Round off to the Nearest Integer). (Given : Atomic masses: \(C\) : \(12.0\, u\), \(H : 1.0\, u , N : 14.0\, u , Br : 80.0\, u ]\)
- A \(1\)
- B \(3\)
- C \(7\)
- D \(9\)
Answer & Solution
Correct Answer
(B) \(3\)
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