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JEE Mains · Chemistry · STD 12 - 9. Amines

A reaction of \(0.1\) mole of Benzylamine with bromomethane gave \(23\, g\) of Benzyl trimethyl ammonium bromide. The number of moles of bromomethane consumed in this reaction are \(n \times 10^{-1},\) when \(n =\ldots...\) (Round off to the Nearest Integer). (Given : Atomic masses: \(C\) : \(12.0\, u\), \(H : 1.0\, u , N : 14.0\, u , Br : 80.0\, u ]\)

  1. A \(1\)
  2. B \(3\)
  3. C \(7\)
  4. D \(9\)
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(B) \(3\)

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