JEE Mains · Chemistry · STD 12 - 6. Haloalkanes and Haloarenes
\(2-\)Methyl propyl bromide reacts with \(C _2 H _5 O ^{-}\)and gives ' \(A\) ' whereas on reaction with \(C _2 H _5 OH\) it gives ' \(B\) '. The mechanism followed in these reactions and the products 'A' and ' \(B\) ' respectively are:
- A \(S _{ N } 2 , A =\) iso-butyl ethyl ether; \(S _{ N } 1, B =\) tertbutyl ethyl ether
- B \(S _{ N } 1, A =\) tert-butyl ethyl ether; \(S _{ N } 1, B =2\) butyl ethyl ether
- C \(S _{ N } 1, A =\) tert-butyl ethyl ether; \(S _{ N } 2, B =\) isobutyl ethyl ether
- D \(S _{ N } 2, A =2\)-butyl ethyl ether; \(S _{ N } 2, B =\) isobutyl ethyl ether
Answer & Solution
Correct Answer
(A) \(S _{ N } 2 , A =\) iso-butyl ethyl ether; \(S _{ N } 1, B =\) tertbutyl ethyl ether
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