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JEE Mains · Chemistry · STD 12 - 6. Haloalkanes and Haloarenes

\(2-\)Methyl propyl bromide reacts with \(C _2 H _5 O ^{-}\)and gives ' \(A\) ' whereas on reaction with \(C _2 H _5 OH\) it gives ' \(B\) '. The mechanism followed in these reactions and the products 'A' and ' \(B\) ' respectively are:

  1. A \(S _{ N } 2 , A =\) iso-butyl ethyl ether; \(S _{ N } 1, B =\) tertbutyl ethyl ether
  2. B \(S _{ N } 1, A =\) tert-butyl ethyl ether; \(S _{ N } 1, B =2\) butyl ethyl ether
  3. C \(S _{ N } 1, A =\) tert-butyl ethyl ether; \(S _{ N } 2, B =\) isobutyl ethyl ether
  4. D \(S _{ N } 2, A =2\)-butyl ethyl ether; \(S _{ N } 2, B =\) isobutyl ethyl ether
Verified Solution

Answer & Solution

Correct Answer

(A) \(S _{ N } 2 , A =\) iso-butyl ethyl ether; \(S _{ N } 1, B =\) tertbutyl ethyl ether

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