JEE Advanced · Mathematics · 30. Vector Algebra
Let \(\mathbf{a}, \mathbf{b}, \mathbf{c}\) be unit vectors such that \(\mathbf{a}+\mathbf{b}+\mathbf{c}=\mathbf{0}\). Which one of the following is correct?
- A
\(\mathbf{a} \times \mathbf{b}=\mathbf{b} \times \mathbf{c}=\mathbf{c} \times \mathbf{a}=\mathbf{0}\)
- B
\(\mathbf{a} \times \mathbf{b}=\mathbf{b} \times \mathbf{c}=\mathbf{c} \times \mathbf{a} \neq \mathbf{0}\)
- C
\(\mathbf{a} \times \mathbf{b}=\mathbf{b} \times \mathbf{c}=\mathbf{a} \times \mathbf{c}=\mathbf{0}\)
- D
\(\mathbf{a} \times \mathbf{b}, \mathbf{b} \times \mathbf{c}, \mathbf{c} \times \mathbf{a}\) are mutually perpendicular
Answer & Solution
Correct Answer
(B)
\(\mathbf{a} \times \mathbf{b}=\mathbf{b} \times \mathbf{c}=\mathbf{c} \times \mathbf{a} \neq \mathbf{0}\)
Step-by-step Solution
Detailed explanation
Since \(\mathbf{a}, \mathbf{b}, \mathbf{c}\) are unit vectors and \(\mathbf{a}+\mathbf{b}+\mathbf{c}=\mathbf{0}\) \(\mathbf{a}, \mathbf{b}\) and \(\mathbf{c}\) represent an equilateral triangle.
\[
\therefore \quad \mathbf{a} \times \mathbf{b}=\mathbf{b} \times \mathbf{c}=\mathbf{c} \times \mathbf{a} \neq \mathbf{0} .
\]
\[
\therefore \quad \mathbf{a} \times \mathbf{b}=\mathbf{b} \times \mathbf{c}=\mathbf{c} \times \mathbf{a} \neq \mathbf{0} .
\]
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