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JEE Advanced · Mathematics · 30. Vector Algebra

Let \(\mathbf{a}, \mathbf{b}, \mathbf{c}\) be unit vectors such that \(\mathbf{a}+\mathbf{b}+\mathbf{c}=\mathbf{0}\). Which one of the following is correct?

  1. A
    \(\mathbf{a} \times \mathbf{b}=\mathbf{b} \times \mathbf{c}=\mathbf{c} \times \mathbf{a}=\mathbf{0}\)
  2. B
    \(\mathbf{a} \times \mathbf{b}=\mathbf{b} \times \mathbf{c}=\mathbf{c} \times \mathbf{a} \neq \mathbf{0}\)
  3. C
    \(\mathbf{a} \times \mathbf{b}=\mathbf{b} \times \mathbf{c}=\mathbf{a} \times \mathbf{c}=\mathbf{0}\)
  4. D
    \(\mathbf{a} \times \mathbf{b}, \mathbf{b} \times \mathbf{c}, \mathbf{c} \times \mathbf{a}\) are mutually perpendicular
Verified Solution

Answer & Solution

Correct Answer

(B)
\(\mathbf{a} \times \mathbf{b}=\mathbf{b} \times \mathbf{c}=\mathbf{c} \times \mathbf{a} \neq \mathbf{0}\)

Step-by-step Solution

Detailed explanation

Since \(\mathbf{a}, \mathbf{b}, \mathbf{c}\) are unit vectors and \(\mathbf{a}+\mathbf{b}+\mathbf{c}=\mathbf{0}\) \(\mathbf{a}, \mathbf{b}\) and \(\mathbf{c}\) represent an equilateral triangle.
\[
\therefore \quad \mathbf{a} \times \mathbf{b}=\mathbf{b} \times \mathbf{c}=\mathbf{c} \times \mathbf{a} \neq \mathbf{0} .
\]
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