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GUJCET · Physics · Semiconductor Electronic: Material, Devices And Simple Circuits

For pn junction, the intensity of electric field is \(1 \times 10^{6} \mathrm{~V} / \mathrm{m}\) and the width of depletion region is 5000 Å. The value of potential barrier \(=\) \(\qquad\) V.

  1. A 0.05
  2. B 0.005
  3. C 0.5
  4. D 5
Verified Solution

Answer & Solution

Correct Answer

(C) 0.5

Step-by-step Solution

Detailed explanation

C.0.5
\(\mathrm{E}=\frac{\mathrm{V}}{d}\)
\(\therefore \mathrm{V}=\mathrm{E} \cdot d\)
\(\therefore \mathrm{V}=1 \times 10^{6} \times 5 \times 10^{-7}\)
\(\therefore \mathrm{V}=5 \times 10^{-1}\)
\(\therefore \mathrm{V}=0.5 \mathrm{~V}\)