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GUJCET · Physics · Semiconductor Electronic: Material, Devices And Simple Circuits
For pn junction, the intensity of electric field is \(1 \times 10^{6} \mathrm{~V} / \mathrm{m}\) and the width of depletion region is 5000 Å. The value of potential barrier \(=\) \(\qquad\) V.
- A 0.05
- B 0.005
- C 0.5
- D 5
Answer & Solution
Correct Answer
(C) 0.5
Step-by-step Solution
Detailed explanation
C.0.5
\(\mathrm{E}=\frac{\mathrm{V}}{d}\)
\(\therefore \mathrm{V}=\mathrm{E} \cdot d\)
\(\therefore \mathrm{V}=1 \times 10^{6} \times 5 \times 10^{-7}\)
\(\therefore \mathrm{V}=5 \times 10^{-1}\)
\(\therefore \mathrm{V}=0.5 \mathrm{~V}\)
\(\mathrm{E}=\frac{\mathrm{V}}{d}\)
\(\therefore \mathrm{V}=\mathrm{E} \cdot d\)
\(\therefore \mathrm{V}=1 \times 10^{6} \times 5 \times 10^{-7}\)
\(\therefore \mathrm{V}=5 \times 10^{-1}\)
\(\therefore \mathrm{V}=0.5 \mathrm{~V}\)
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