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GUJCET · Maths · Linear Programming
The maximum value of \(Z=60 x+10 y\) whose, corner points are \((10,0),(2,4),(1,5)\) and \((0,8)\) is _________ .
- A 700
- B 800
- C 600
- D 110
Answer & Solution
Correct Answer
(C) 600
Step-by-step Solution
Detailed explanation
\(Z(10,0) = 60(10) + 10(0) = 600\) \(Z(2,4) = 60(2) + 10(4) = 120 + 40 = 160\)
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