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GUJCET · Maths · Inverse Trigonometric Functions
\(\begin{array}{l}\tan ^2\left(\sec ^{-1} 3\right)+\operatorname{cosec}^2\left(\cot ^{-1} 2\right) \\+\cos ^2\left(\cos ^{-1} \frac{2}{3}+\sin ^{-1} \frac{2}{3}\right)=\end{array}\) ____________ .
- A 14
- B 15
- C 16
- D 13
Answer & Solution
Correct Answer
(D) 13
Step-by-step Solution
Detailed explanation
\(\tan ^2\left(\sec ^{-1} 3\right) = \left(\sec\left(\sec ^{-1} 3\right)\right)^2 - 1 = 3^2 - 1 = 8\) \(\operatorname{cosec}^2\left(\cot ^{-1} 2\right) = 1 + \left(\cot\left(\cot ^{-1} 2\right)\right)^2 = 1 + 2^2 = 5\)
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