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GUJCET · Chemistry · Solutions
What is the osmotic pressure (pi) of 0.02M solution of NaCl ?
- A 0.01 RT
- B 0.02 RT
- C 0.04 RT
- D 0.002 RT
Answer & Solution
Correct Answer
(C) 0.04 RT
Step-by-step Solution
Detailed explanation
C
\(\pi= icRT =2 \times 0.02 RT =0.04 RT\)
\(\pi= icRT =2 \times 0.02 RT =0.04 RT\)
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