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GUJCET · Chemistry · Chemical Kinetics
The value of rate constant for a first order reaction is \(2.303 \times 10^{-2} sec ^{-1}\). What will be the time required to reduce the concentration to \(\frac{1}{10}\) th of its initial concentration ?
- A 10 second
- B 100 second
- C 2303 second
- D 230.3 second
Answer & Solution
Correct Answer
(B) 100 second
Step-by-step Solution
Detailed explanation
B
\(\begin{array}{l}k=\frac{2.303}{t} \log \frac{1}{\frac{1}{10}} \\ t=\frac{2.303}{2.303 \times 10^{-2}} \log 10=10^2 Sec \end{array}\)
\(\begin{array}{l}k=\frac{2.303}{t} \log \frac{1}{\frac{1}{10}} \\ t=\frac{2.303}{2.303 \times 10^{-2}} \log 10=10^2 Sec \end{array}\)
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