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GUJCET · Chemistry · Chemical Kinetics
The half-life for radioactive decay of \({ }^{14} C\) is 5730 years. An archaeological artifact containing wood had only \(80 \%\) of the \({ }^{14} C\) found in a living tree. Which is the correct formula for age \((t)\) of the sample?
- A \(t=\frac{0.3}{5730} \log \frac{20}{100}\)
- B \(t=\frac{5730}{0.3} \log \frac{100}{80}\)
- C \(t=\frac{0.3}{5730} \log \frac{100}{20}\)
- D \(t=\frac{5730}{0.3} \log \frac{80}{100}\)
Answer & Solution
Correct Answer
(B) \(t=\frac{5730}{0.3} \log \frac{100}{80}\)
Step-by-step Solution
Detailed explanation
\(t = \frac{t_{1/2}}{\log 2} \log \left( \frac{N_0}{N} \right)\) \(t = \frac{5730}{0.3} \log \left( \frac{100}{80} \right)\)
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