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GUJCET · Chemistry · Chemical Kinetics

The half-life for radioactive decay of \({ }^{14} C\) is 5730 years. An archaeological artifact containing wood had only \(80 \%\) of the \({ }^{14} C\) found in a living tree. Which is the correct formula for age \((t)\) of the sample?

  1. A \(t=\frac{0.3}{5730} \log \frac{20}{100}\)
  2. B \(t=\frac{5730}{0.3} \log \frac{100}{80}\)
  3. C \(t=\frac{0.3}{5730} \log \frac{100}{20}\)
  4. D \(t=\frac{5730}{0.3} \log \frac{80}{100}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(t=\frac{5730}{0.3} \log \frac{100}{80}\)

Step-by-step Solution

Detailed explanation

\(t = \frac{t_{1/2}}{\log 2} \log \left( \frac{N_0}{N} \right)\) \(t = \frac{5730}{0.3} \log \left( \frac{100}{80} \right)\)