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GUJCET · Chemistry · Solutions

Calculate the mass of Glucose \(\left( C _6 H _{12} O _6\right)\) required in making 2.5 kg of 0.25 molal aqueous solution.[Atomic wt : \(H =1, O =16, C =12 amu\) ]

  1. A 135.0 g
  2. B 107.65 g
  3. C 90.0 g
  4. D 112.5 g
Verified Solution

Answer & Solution

Correct Answer

(B) 107.65 g

Step-by-step Solution

Detailed explanation

\(M_{C_6H_{12}O_6} = 6(12) + 12(1) + 6(16) = 180 \text{ g/mol}\) \(m = \frac{\text{moles of solute}}{\text{mass of solvent (kg)}}\)