CUET · PHYSICS · PYQ PAPER 2023
Which of the following is correct for a parallel plate capacitor of separation 'd' when a slab of material of dielectric constant \(k\) has the same area as the plate of capacitor but has a thickness \(d / 2\) is inserted between the plates?
A. Its capacitance decreases
B. Its capacitance increases
C. \(C=C_0\left(\frac{2 k}{k+1}\right)\)
D. \(C=C_0\left(\frac{k+1}{2 k}\right)\)
E. Charge remains same.
Choose the correct answer from the options given below:
- A A, D and E Only
- B A and E Only
- C B and E Only
- D B, C and E Only
Answer & Solution
Correct Answer
(D) B, C and E Only
Step-by-step Solution
Detailed explanation
\(C_0 = \frac{\epsilon_0 A}{d}\) \(C_1 = \frac{k\epsilon_0 A}{d/2}\) \(C_2 = \frac{\epsilon_0 A}{d/2}\) \(\frac{1}{C} = \frac{1}{C_1} + \frac{1}{C_2} = \frac{d}{2k\epsilon_0 A} + \frac{d}{2\epsilon_0 A} = \frac{d}{2\epsilon_0 A} \left(\frac{1}{k}+1\right)\)…
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