CUET · PHYSICS · PYQ PAPER 2025
What will be the expression for the energy of a photon of wavelength \(\lambda\) is:
- A \(\frac{hc}{\lambda}\)
- B \(\frac{\lambda}{hc}\)
- C \(hc\lambda\)
- D \(\frac{hλ}{c}\)
Answer & Solution
Correct Answer
(A) \(\frac{hc}{\lambda}\)
Step-by-step Solution
Detailed explanation
The energy of a photon is calculated using the relation \(E=h \nu\). Since the frequency \((\nu)\) is equal to the speed of light (c) divided by the wavelength ( \(\lambda\) ), substituting this gives the expression: \(E=\frac{h c}{\lambda}\) This indicates that a photon's…
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