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CUET · PHYSICS · PYQ PAPER 2025

What will be the expression for the energy of a photon of wavelength \(\lambda\) is:

  1. A \(\frac{hc}{\lambda}\)
  2. B \(\frac{\lambda}{hc}\)
  3. C \(hc\lambda\)
  4. D \(\frac{hλ}{c}\)
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Answer & Solution

Correct Answer

(A) \(\frac{hc}{\lambda}\)

Step-by-step Solution

Detailed explanation

The energy of a photon is calculated using the relation \(E=h \nu\). Since the frequency \((\nu)\) is equal to the speed of light (c) divided by the wavelength ( \(\lambda\) ), substituting this gives the expression: \(E=\frac{h c}{\lambda}\) This indicates that a photon's…
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