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CUET · PHYSICS · PYQ PAPER 2023

What is the total energy of electron in the \( n^{th} \) stationary orbit of hydrogen atom ?

  1. A \( \frac{13.6}{n^2} \text{ J} \)
  2. B \( -\frac{13.6}{n^2} \text{ eV} \)
  3. C \( 0.53n^2 \text{ J} \)
  4. D \( \frac{0.53}{n^2} \text{ eV} \)
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Answer & Solution

Correct Answer

(B) \( -\frac{13.6}{n^2} \text{ eV} \)

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Detailed explanation

According to Bohr's model, the energy of an electron is quantized and given by the formula \(E_n=-13.6 \frac{Z^2}{n^2} eV\). For a hydrogen atom \((Z=1)\), this simplifies to \(-\frac{13.6}{n^2} eV\), where the negative sign indicates that the electron is bound to the nucleus.…
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