CUET · PHYSICS · PYQ PAPER 2023
What is the relation between phase difference \((\Delta \theta)\) and path difference \((\Delta x)\) ?
- A \(\Delta \theta=\frac{2 \pi}{\lambda} \Delta x\)
- B \(\Delta x =\frac{2 \pi \lambda}{\Delta \theta}\)
- C \(\Delta \theta=2 \pi \lambda \Delta x\)
- D \(\Delta x =\frac{2 \lambda \Delta \theta}{\pi}\)
Answer & Solution
Correct Answer
(A) \(\Delta \theta=\frac{2 \pi}{\lambda} \Delta x\)
Step-by-step Solution
Detailed explanation
This formula is based on the fact that a full wavelength \((\lambda)\) corresponds to a complete phase shift of \(2 \pi\) radians. By setting up the ratio \(\frac{\Delta \theta}{2 \pi}=\frac{\Delta x}{\lambda}\) and solving for \(\Delta \theta\), you get this standard wave…
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