CUET · PHYSICS · PYQ PAPER 2023
What is the magnetic force acting on a proton (charge \( + 1.6 \times 10^{-19} \text{ C} \)) moving at an angle of \( 30^{\circ} \) across a magnetic field of \( 5.3 \times 10^{-3} \text{ T} \) at a speed of \( 3.0 \times 10^5 \text{ m s}^{-1} \)?
- A \( 1.272 \times 10^{-19} \text{ N} \)
- B \( 1.3 \times 10^{-16} \text{ N} \)
- C \( 1.272 \times 10^{-16} \text{ N} \)
- D \( 2.2 \times 10^{-16} \text{ N} \)
Answer & Solution
Correct Answer
(C) \( 1.272 \times 10^{-16} \text{ N} \)
Step-by-step Solution
Detailed explanation
\( F = qvB \sin\theta \) \( F = (1.6 \times 10^{-19} \text{ C}) (3.0 \times 10^5 \text{ m s}^{-1}) (5.3 \times 10^{-3} \text{ T}) \sin(30^{\circ}) = 1.272 \times 10^{-16} \text{ N} \)
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