CUET · PHYSICS · PYQ PAPER 2023
What is the force experienced by an electron moving with velocity of \(0.5 c\) in a magnetic field \(\vec{B}\) of \(2 T\) ? The angle between the velocity vector and \(\vec{B}\) is \(90^{\circ}\)
( \(c\) is the velocity of light, \(e=1.6 \times 10^{-19} C\) )
- A \(4.8 \times 10^{-10} N\)
- B \(4.8 \times 10^{-11} N\)
- C \(4.8 \times 10^{-12} N\)
- D \(4.8 \times 10^{-13} N\)
Answer & Solution
Correct Answer
(B) \(4.8 \times 10^{-11} N\)
Step-by-step Solution
Detailed explanation
\(v = 0.5 \times 3 \times 10^8 m/s = 1.5 \times 10^8 m/s\) \(F = qvB \sin\theta\) \(F = (1.6 \times 10^{-19} C)(1.5 \times 10^8 m/s)(2 T) \sin(90^{\circ})\) \(F = 4.8 \times 10^{-11} N\)
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