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CUET · PHYSICS · PYQ PAPER 2023

What is the de Broglie wavelength associated with an electron accelerated through a potential difference of 144 V?

  1. A 0.0102 nm
  2. B 1.022 nm
  3. C 0.0102 m
  4. D 0.102 nm
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Answer & Solution

Correct Answer

(A) 0.0102 nm

Step-by-step Solution

Detailed explanation

\( \lambda = \frac{1.226}{\sqrt{V}} \, \text{nm} \) \( \lambda = \frac{1.226}{\sqrt{144}} \, \text{nm} \) \( \lambda = \frac{1.226}{12} \, \text{nm} \) \( \lambda = 0.10216... \, \text{nm} \) \( \lambda \approx 0.102 \, \text{nm} \)
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