CUET · PHYSICS · PYQ PAPER 2025
What is the de-Broglie wavelength associated with an electron, accelerated through a potential difference of 10 kV
- A 0.123 nm
- B 0.0123 nm
- C 12.3 nm
- D 1.23 nm
Answer & Solution
Correct Answer
(B) 0.0123 nm
Step-by-step Solution
Detailed explanation
\( \lambda = \frac{1.226}{\sqrt{V}} \text{ nm} \) \( \lambda = \frac{1.226}{\sqrt{10 \times 10^3}} \text{ nm} \) \( \lambda = \frac{1.226}{100} \text{ nm} \) \( \lambda = 0.0123 \text{ nm} \)
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