CUET · PHYSICS · PYQ PAPER 2023
What are the respective numbers of \( \alpha \) and \( \beta \) particles emitted respectively in the following radioactive decay?
\( {}^{200}_{90}X \rightarrow {}^{168}_{80}Y \)
- A 8 and 8
- B 8 and 6
- C 6 and 8
- D 6 and 6
Answer & Solution
Correct Answer
(B) 8 and 6
Step-by-step Solution
Detailed explanation
Mass number: \( 200 = 168 + 4n_\alpha \) \( 4n_\alpha = 32 \) \( n_\alpha = 8 \) Atomic number: \( 90 = 80 + 2n_\alpha - n_\beta \) \( 90 = 80 + 2(8) - n_\beta \) \( 90 = 80 + 16 - n_\beta \) \( 90 = 96 - n_\beta \) \( n_\beta = 6 \)
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