CUET · PHYSICS · PYQ PAPER 2023
Using the given information, calculate the mass defect of the \({ }_8^{16} O\) nucleus in \(MeV / c ^2\).
Mass of electron, \(m_e=0.00055 u\)
Mass of proton, \(m_p=1.00727 u\)
Mass of neutron, \(m_n=1.00866 u\)
Experimental mass of nucleus \(=15.99053 u\)
\(1 u=931.5 MeV / c^2\)
Choose the correct answer from the options given below:
- A \(150.5 MeV / c ^2\)
- B \(127 .5 MeV / c^2\)
- C \(107.5 MeV / c^2\)
- D \(680.0 MeV / c^2\)
Answer & Solution
Correct Answer
(B) \(127 .5 MeV / c^2\)
Step-by-step Solution
Detailed explanation
\(Z=8, N=16-8=8\) \(M_{theo} = 8 m_p + 8 m_n = 8(1.00727 u) + 8(1.00866 u) = 8.05816 u + 8.06928 u = 16.12744 u\) \(\Delta m = M_{theo} - M_{exp} = 16.12744 u - 15.99053 u = 0.13691 u\)…
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