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CUET · PHYSICS · PYQ PAPER 2025

Two sources of equal emf are connected in series. This combination is connected to an external resistance R.
The internal resistance of two sources are \( r_1 \) and \( r_2 \) (\( r_2 > r_1 \)).
If the potential difference across the source of internal resistance \( r_2 \) is zero, then R equals to:

  1. A \( R = r_2 - r_1 \)
  2. B \( R = r_1 - r_2 \)
  3. C \( R = r_1 \)
  4. D \( R = 0 \)
Verified Solution

Answer & Solution

Correct Answer

(A) \( R = r_2 - r_1 \)

Step-by-step Solution

Detailed explanation

\( V_2 = E - I r_2 = 0 \Rightarrow E = I r_2 \) \( I = \frac{2E}{R + r_1 + r_2} \) \( E = \left( \frac{2E}{R + r_1 + r_2} \right) r_2 \) \( R + r_1 + r_2 = 2 r_2 \) \( R = r_2 - r_1 \)
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