CUET · PHYSICS · PYQ PAPER 2023
Two sitar strings A and B playing a note are slightly out of tune and produce beats of frequency 5 Hz. The tension in string B is slightly increased and beat frequency becomes 3 Hz. What is the original frequency of B if frequency of A is 427 Hz?
- A 432 Hz
- B 430 Hz
- C 424 Hz
- D 422 Hz
Answer & Solution
Correct Answer
(D) 422 Hz
Step-by-step Solution
Detailed explanation
\(f_A = 427 \text{ Hz}\) \(|f_A - f_B| = 5 \text{ Hz} \implies f_B = f_A \pm 5 \text{ Hz}\) \(f_B = 427 + 5 = 432 \text{ Hz}\) or \(f_B = 427 - 5 = 422 \text{ Hz}\) Increasing tension in string B increases its frequency, so \(f_B' > f_B\). New beat frequency…
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