CUET · PHYSICS · PYQ PAPER 2025
Two resistances, \( 6 \, \Omega \) and \( 3 \, \Omega \), are connected in parallel to an electrical cell of EMF 6 V and \( 1 \, \Omega \) internal resistance. The reading of the voltmeter connected to the circuit will be:
- A 4 V
- B 2.4 V
- C 3 V
- D 6 V
Answer & Solution
Correct Answer
(A) 4 V
Step-by-step Solution
Detailed explanation
\( R_p = \frac{R_1 R_2}{R_1 + R_2} = \frac{6 \times 3}{6 + 3} = 2 \, \Omega \) \( I = \frac{E}{R_p + r} = \frac{6}{2 + 1} = \frac{6}{3} = 2 \, A \) \( V = I R_p = 2 \times 2 = 4 \, V \)
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