CUET · PHYSICS · PYQ PAPER 2025
Two positive point charges of \(q_1=0.2 \mu C\) and \(q_2=0.01 \mu C\) are placed \(r_i=10 cm\) apart. The work done in reducing the distance to \(r_f=5 cm\) will be
- A \(1.8 \times 10^{-4} J\)
- B \(1.8 \times 10^{-6} J\)
- C 0.018 J
- D \(1.8 \times 10^{-3} J\)
Answer & Solution
Correct Answer
(A) \(1.8 \times 10^{-4} J\)
Step-by-step Solution
Detailed explanation
\(W = k q_1 q_2 \left( \frac{1}{r_f} - \frac{1}{r_i} \right)\) \(W = (9 \times 10^9) (0.2 \times 10^{-6}) (0.01 \times 10^{-6}) \left( \frac{1}{0.05} - \frac{1}{0.1} \right)\) \(W = (9 \times 10^9) (2 \times 10^{-15}) (20 - 10)\) \(W = (18 \times 10^{-6}) (10)\)…
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