CUET · PHYSICS · PYQ PAPER 2025
Two point charges + 200 \( \mu \)C are placed at a distance of 2 mm from each other in a uniform electric field of \( 10^5 \text{ N/C} \), such that the line joining the negative to positive charge makes an angle 30° with the field. The torque acting on the system is:
- A 0.02 Nm
- B 0.2 Nm
- C 2.02 Nm
- D 0.002 Nm
Answer & Solution
Correct Answer
(A) 0.02 Nm
Step-by-step Solution
Detailed explanation
\( p = q(2a) = (200 \times 10^{-6} \, \text{C})(2 \times 10^{-3} \, \text{m}) = 4 \times 10^{-7} \, \text{C m} \) \( \tau = pE\sin\theta = (4 \times 10^{-7} \, \text{C m})(10^5 \, \text{N/C})\sin(30^\circ) = 0.02 \, \text{Nm} \)
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