CUET · PHYSICS · PYQ PAPER 2024
Two parallel plate capacitors of capacitances \(2 \, \mu\text{F}\) and \(3 \, \mu\text{F}\) are joined in series and connected to a battery of V volts. The values of potential across the two capacitors \(V_1\) and \(V_2\) and energy stored in them \(U_1\) and \(U_2\) are related as :
- A \(\frac{V_2}{V_1} = \frac{U_2}{U_1} = \frac{2}{3}\)
- B \(\frac{V_2}{V_1} = \frac{U_2}{U_1} = \frac{3}{2}\)
- C \(\frac{V_2}{V_1} = \frac{2}{3} , \frac{U_2}{U_1} = \frac{3}{2}\)
- D \(\frac{V_2}{V_1} = \frac{3}{2} , \frac{U_2}{U_1} = \frac{2}{3}\)
Answer & Solution
Correct Answer
(A) \(\frac{V_2}{V_1} = \frac{U_2}{U_1} = \frac{2}{3}\)
Step-by-step Solution
Detailed explanation
\(Q_1 = Q_2 = Q\) \(\frac{V_2}{V_1} = \frac{Q/C_2}{Q/C_1} = \frac{C_1}{C_2} = \frac{2 \, \mu\text{F}}{3 \, \mu\text{F}} = \frac{2}{3}\) \(\frac{U_2}{U_1} = \frac{Q^2/(2C_2)}{Q^2/(2C_1)} = \frac{C_1}{C_2} = \frac{2 \, \mu\text{F}}{3 \, \mu\text{F}} = \frac{2}{3}\)
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