CUET · PHYSICS · PYQ PAPER 2025
Two parallel conductors each carrying a current of 10 mA in opposite directions are placed at a distance 10 cm apart. The force per unit length between two conductors is
- A \( 10 \times 10^{-4} (\frac{\mu_0}{2\pi}) \, N/m \)
- B \(5 \times 10^{-4} (\frac{\mu_0}{2\pi}) \, N/m \)
- C \( 20 \times 10^{-4} (\frac{\mu_0}{2\pi}) \, N/m \)
- D \( 1 \times 10^{-4} (\frac{\mu_0}{2\pi}) \, N/m \)
Answer & Solution
Correct Answer
(A) \( 10 \times 10^{-4} (\frac{\mu_0}{2\pi}) \, N/m \)
Step-by-step Solution
Detailed explanation
\( \frac{F}{L} = \frac{\mu_0 I_1 I_2}{2\pi r} \) \( \frac{F}{L} = \frac{\mu_0 (10 \times 10^{-3})(10 \times 10^{-3})}{2\pi (0.1)} \) \( \frac{F}{L} = \frac{\mu_0 (100 \times 10^{-6})}{2\pi (0.1)} \) \( \frac{F}{L} = 10 \times 10^{-4} (\frac{\mu_0}{2\pi}) \, N/m \)
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