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CUET · PHYSICS · PYQ PAPER 2025

Two long straight parallel wires are carrying charges \( \lambda_1 \) and \( \lambda_2 \) per unit length, respectively. The separation between their axes is d. The magnitude of the force exerted on unit length of one wire due to the charge on the other wire is

  1. A \( f = \frac{\lambda_1 \lambda_2}{2\pi \epsilon_0 d} \)
  2. B \( f = \frac{\lambda_1 \lambda_2}{4\pi \epsilon_0 d} \)
  3. C \( f = \frac{\lambda_1 \lambda_2}{4\pi \epsilon_0 d^2} \)
  4. D \( f = \frac{\lambda_1 \lambda_2}{(2\pi \epsilon_0 d)^2} \)
Verified Solution

Answer & Solution

Correct Answer

(A) \( f = \frac{\lambda_1 \lambda_2}{2\pi \epsilon_0 d} \)

Step-by-step Solution

Detailed explanation

\( E_1 = \frac{\lambda_1}{2\pi \epsilon_0 d} \) \( f = E_1 \lambda_2 \) \( f = \frac{\lambda_1 \lambda_2}{2\pi \epsilon_0 d} \)