CUET · PHYSICS · PYQ PAPER 2025
Two long and parallel straight wires, each carrying current \(I\) in the same direction, are separated by a distance of 40 cm. If the force of attraction per metre between them is \(2 \times 10^{-6} \text{ N/m}\), the value of \(I\) will be: (Given: \(\mu_0 = 4\pi \times 10^{-7} \text{ T}⋅m⋅A^{-1}\))
- A 0.56 A
- B 0.63 A
- C 2 A
- D 4 A
Answer & Solution
Correct Answer
(C) 2 A
Step-by-step Solution
Detailed explanation
\( F/L = \frac{\mu_0 I^2}{2\pi r} \) \( I^2 = \frac{2\pi r (F/L)}{\mu_0} \) \( I = \sqrt{\frac{2\pi (0.40 \text{ m}) (2 \times 10^{-6} \text{ N/m})}{4\pi \times 10^{-7} \text{ T}⋅m⋅A^{-1}}} \) \( I = \sqrt{\frac{1.6\pi \times 10^{-6}}{4\pi \times 10^{-7}}} \) \( I = \sqrt{4} \)…
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