CUET · PHYSICS · PYQ PAPER 2025
Two identical point charges placed at a distance 'r' apart exert a force F on each other. If each charge is halved and the distance between them is doubled, then the new force acting on each charge would be
- A 4 F
- B F / 4
- C F / 16
- D 8 F
Answer & Solution
Correct Answer
(C) F / 16
Step-by-step Solution
Detailed explanation
\( F = k \frac{q^2}{r^2} \) \( F' = k \frac{(q/2)^2}{(2r)^2} \) \( F' = k \frac{q^2/4}{4r^2} = k \frac{q^2}{16r^2} = \frac{1}{16} \left( k \frac{q^2}{r^2} \right) = \frac{F}{16} \)
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