ExamBro
ExamBro
CUET · PHYSICS · PYQ PAPER 2025

Two identical point charges placed at a distance 'r' apart exert a force F on each other. If each charge is halved and the distance between them is doubled, then the new force acting on each charge would be

  1. A 4 F
  2. B F / 4
  3. C F / 16
  4. D 8 F
Verified Solution

Answer & Solution

Correct Answer

(C) F / 16

Step-by-step Solution

Detailed explanation

\( F = k \frac{q^2}{r^2} \) \( F' = k \frac{(q/2)^2}{(2r)^2} \) \( F' = k \frac{q^2/4}{4r^2} = k \frac{q^2}{16r^2} = \frac{1}{16} \left( k \frac{q^2}{r^2} \right) = \frac{F}{16} \)