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CUET · PHYSICS · PYQ PAPER 2023

Two identical photo cathode receive the light of frequencies \(f_1\) and \(f_2\) respectively. The velocities of photoelectrons coming out are \(V_1\) and \(V_2\) respectively. The value of \((V_1^2 - V_2^2)\) will be:

  1. A \(\frac{2h}{m} \sqrt{f_1 - f_2}\)
  2. B \(\frac{2h}{m} (f_1 - f_2)\)
  3. C \(\frac{2h}{m} (f_1^2 - f_2^2)\)
  4. D \(\frac{2h}{m} (f_1 - f_2)^2\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\frac{2h}{m} (f_1 - f_2)\)

Step-by-step Solution

Detailed explanation

\(h f_1 = \phi + \frac{1}{2} m V_1^2\) \(h f_2 = \phi + \frac{1}{2} m V_2^2\) \(h(f_1 - f_2) = \frac{1}{2}m(V_1^2 - V_2^2)\) \(V_1^2 - V_2^2 = \frac{2h}{m}(f_1 - f_2)\)
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