CUET · PHYSICS · PYQ PAPER 2023
Two identical photo cathode receive the light of frequencies \(f_1\) and \(f_2\) respectively. The velocities of photoelectrons coming out are \(V_1\) and \(V_2\) respectively. The value of \((V_1^2 - V_2^2)\) will be:
- A \(\frac{2h}{m} \sqrt{f_1 - f_2}\)
- B \(\frac{2h}{m} (f_1 - f_2)\)
- C \(\frac{2h}{m} (f_1^2 - f_2^2)\)
- D \(\frac{2h}{m} (f_1 - f_2)^2\)
Answer & Solution
Correct Answer
(B) \(\frac{2h}{m} (f_1 - f_2)\)
Step-by-step Solution
Detailed explanation
\(h f_1 = \phi + \frac{1}{2} m V_1^2\) \(h f_2 = \phi + \frac{1}{2} m V_2^2\) \(h(f_1 - f_2) = \frac{1}{2}m(V_1^2 - V_2^2)\) \(V_1^2 - V_2^2 = \frac{2h}{m}(f_1 - f_2)\)
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