CUET · PHYSICS · PYQ PAPER 2023
Two cylindrical wires of the same material have their lengths in the ratio 2: 1 and their diameters in the ratio \(1: 3\). The ratio of the resistance of thinner wire to that of thicker wire is:
- A \(1: 9\)
- B \(1: 18\)
- C \(18: 1\)
- D \(9: 1\)
Answer & Solution
Correct Answer
(C) \(18: 1\)
Step-by-step Solution
Detailed explanation
\(R = \rho \frac{4L}{\pi d^2}\) \(\frac{R_{thinner}}{R_{thicker}} = \frac{L_{thinner}}{L_{thicker}} \times \left(\frac{d_{thicker}}{d_{thinner}}\right)^2\) \(\frac{R_{thinner}}{R_{thicker}} = \left(\frac{2}{1}\right) \times \left(\frac{3}{1}\right)^2\)…
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