CUET · PHYSICS · PYQ PAPER 2025
Two concentric coils \(X\) and \(Y\), each of radius \(2 \pi cm\), are placed at right angles to each other. If \(X\) and \(Y\) carry 4 A and 3 A currents, respectively, then the value of the magnetic field (in \(Wb m ^{-2}\) ) at the centre of the coils is (Take \(\mu_0=4 \pi \times 10^{-7} Wb A ^{-1} m^{-1}\) )
- A \(1.7 \times 10^{-5}\)
- B \(2.6 \times 10^{-5}\)
- C zero
- D \(5 \times 10^{-5} Wb m ^{-2}\)
Answer & Solution
Correct Answer
(D) \(5 \times 10^{-5} Wb m ^{-2}\)
Step-by-step Solution
Detailed explanation
\(B_{net} = \frac{\mu_0}{2R} \sqrt{I_X^2 + I_Y^2}\) \(B_{net} = \frac{4 \pi \times 10^{-7}}{2 \times (2 \pi \times 10^{-2})} \sqrt{4^2 + 3^2}\) \(B_{net} = \frac{4 \pi \times 10^{-7}}{4 \pi \times 10^{-2}} \times 5\) \(B_{net} = 10^{-5} \times 5 = 5 \times 10^{-5} Wb m^{-2}\)
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