CUET · PHYSICS · PYQ PAPER 2023
Two coils have a mutual inductance 0.005 H . The current changes in the first coil according to the equation \(I=I_0 \sin \omega t\), where \(I_0=10 A\), and \(\omega=100 \pi rad / s\). The maximum value of emf in the second coil is (in V) :
- A \(2 \pi\)
- B \(5 \pi\)
- C \(6 \pi\)
- D \(12 \pi\)
Answer & Solution
Correct Answer
(B) \(5 \pi\)
Step-by-step Solution
Detailed explanation
\( \varepsilon = -M \frac{dI}{dt} \) \( \frac{dI}{dt} = \frac{d}{dt}(I_0 \sin \omega t) = I_0 \omega \cos \omega t \) \( \varepsilon_{max} = M (I_0 \omega) = 0.005 \times 10 \times 100 \pi \) \( \varepsilon_{max} = 5 \pi \, V \)
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