CUET · PHYSICS · PYQ PAPER 2023
Two charges \( q_1 = 4 \times 10^{-7} \text{ C} \) and \( q_2 = -6 \times 10^{-7} \text{ C} \) are located 3 m apart. At what point on the line joining the two charges is the electric potential zero? (Consider potential zero at infinity.)
- A 1.5 meter from charge \( q_1 \)
- B 1.5 meter from charge \( q_2 \)
- C 1.2 meter from charge \( q_1 \)
- D 1.2 meter from charge \( q_2 \)
Answer & Solution
Correct Answer
(C) 1.2 meter from charge \( q_1 \)
Step-by-step Solution
Detailed explanation
\( V = V_1 + V_2 = 0 \) \( k\frac{q_1}{x} + k\frac{q_2}{d-x} = 0 \) \( \frac{q_1}{x} = -\frac{q_2}{d-x} \) \( q_1(d-x) = -q_2 x \) \( (4 \times 10^{-7})(3-x) = -(-6 \times 10^{-7})x \) \( 4(3-x) = 6x \) \( 12 - 4x = 6x \) \( 12 = 10x \) \( x = 1.2 \text{ m} \)
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