CUET · PHYSICS · PYQ PAPER 2025
Two charges of equal magnitude and at distance r exert a force F on each other. If each charge is doubled and the distance between them is halved, then the new force acting on each charge will be
- A 4F
- B 16F
- C 2F
- D 12F
Answer & Solution
Correct Answer
(B) 16F
Step-by-step Solution
Detailed explanation
\(F = k \frac{q^2}{r^2}\) \(F' = k \frac{(2q)(2q)}{(r/2)^2}\) \(F' = k \frac{4q^2}{r^2/4}\) \(F' = 16 k \frac{q^2}{r^2}\) \(F' = 16F\)
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