CUET · PHYSICS · PYQ PAPER 2025
Two cells with internal resistances \( r_1 \) and \( r_2 \) are connected across the load resistance R as shown in the figure. The values of \( r_1, r_2 \) and R are (1/2) \( \Omega \), (1/3) \( \Omega \) and (9/5) \( \Omega \), respectively. The current through R is:

- A 7/5 A
- B 7/15 A
- C 15/7 A
- D 7/10 A
Answer & Solution
Correct Answer
(D) 7/10 A
Step-by-step Solution
Detailed explanation
\( \frac{1}{r_{eq}} = \frac{1}{r_1} + \frac{1}{r_2} = \frac{1}{1/2} + \frac{1}{1/3} = 2 + 3 = 5 \) \( r_{eq} = 1/5 \, \Omega \) \( \frac{E_{eq}}{r_{eq}} = \frac{E_1}{r_1} + \frac{E_2}{r_2} = \frac{2}{1/2} + \frac{1}{1/3} = 4 + 3 = 7 \)…
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