CUET · PHYSICS · PYQ PAPER 2025
Two cells of emf 2 V and 4 V and internal resistance of \( 0.5 \text{ } \Omega \) each are connected with an external resistor of resistance \( 3 \text{ } \Omega \) as shown in the figure. The terminal potential difference of 2 V cell is:

- A 2.25 V
- B 1.75 V
- C 1.5 V
- D 2.5 V
Answer & Solution
Correct Answer
(A) 2.25 V
Step-by-step Solution
Detailed explanation
\(I = \frac{E_2 - E_1}{R + r_1 + r_2}\) \(I = \frac{4 \text{ V} - 2 \text{ V}}{3 \text{ } \Omega + 0.5 \text{ } \Omega + 0.5 \text{ } \Omega} = \frac{2 \text{ V}}{4 \text{ } \Omega} = 0.5 \text{ A}\) Since current enters the positive terminal of the 2 V cell, it is being…
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