CUET · PHYSICS · PYQ PAPER 2025
Two capacitors of capacitances of \( 6 \, \mu F \) and \( 12 \, \mu F \) are connected in series with a 12 V battery. The total energy stored in the combination is
- A 1296 \( \mu J \)
- B 96 \( \mu J \)
- C 192 \( \mu J \)
- D 288 \( \mu J \)
Answer & Solution
Correct Answer
(D) 288 \( \mu J \)
Step-by-step Solution
Detailed explanation
\( C_{eq} = \frac{C_1 C_2}{C_1 + C_2} = \frac{(6 \, \mu F)(12 \, \mu F)}{6 \, \mu F + 12 \, \mu F} = 4 \, \mu F \) \( E = \frac{1}{2} C_{eq} V^2 = \frac{1}{2} (4 \, \mu F) (12 \, V)^2 = 288 \, \mu J \)
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