CUET · PHYSICS · PYQ PAPER 2025
Two batteries of emf 5 V with internal resistance 2 \( \Omega \) and 6 V with internal resistance 3 \( \Omega \) are connected in series with an external resistor. If the current in the circuit is 0.5 A, then the resistance of the resistor is
- A 15 \( \Omega \)
- B 17 \( \Omega \)
- C 19 \( \Omega \)
- D 21 \( \Omega \)
Answer & Solution
Correct Answer
(B) 17 \( \Omega \)
Step-by-step Solution
Detailed explanation
\( E_{total} = E_1 + E_2 = 5 \text{ V} + 6 \text{ V} = 11 \text{ V} \) \( r_{total} = r_1 + r_2 = 2 \Omega + 3 \Omega = 5 \Omega \) \( R_{circuit} = \frac{E_{total}}{I} = \frac{11 \text{ V}}{0.5 \text{ A}} = 22 \Omega \)…
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